The symmetric difference of two sets AAA and BBB is given by A△B=(A∖B)∪(B∖A)=(A∪B)∖(A∩B).A\triangle B = (A\setminus B)\cup(B\setminus A) = (A\cup B)\setminus (A\cap B).A△B=(A∖B)∪(B∖A)=(A∪B)∖(A∩B). It is the set of elements that are in exactly one of AAA or BBB.
Wikidata ID: Q1147242