MathGloss

Let (X,Σ)(X,\Sigma) be a measurable space and let μ\mu and ν\nu be two measures on (X,Σ)(X,\Sigma). Then μ\mu is absolutely continuous with respect to ν\nu if μ(A)=0\mu(A) =0 for every AΣA\in \Sigma for which ν(A)=0\nu(A)=0.

Wikidata ID: Q20827138